Math Problem Statement

5 ^ 2 * (1/125) ^ - 1 / 25 =

Solution

Let's break down the expression step by step:

Given: 52×(1125)1÷255^2 \times \left(\frac{1}{125}\right)^{-1} \div 25

Step 1: Simplify 525^2

52=255^2 = 25

Step 2: Simplify (1125)1\left(\frac{1}{125}\right)^{-1}

Taking the reciprocal of 1125\frac{1}{125} gives: (1125)1=125\left(\frac{1}{125}\right)^{-1} = 125

Step 3: Multiply the results from Step 1 and Step 2

25×125=312525 \times 125 = 3125

Step 4: Divide by 25

312525=125\frac{3125}{25} = 125

Thus, the value of the expression is: 125\boxed{125}

Do you want more details, or have any questions?

Here are 5 related questions:

  1. How do you calculate powers of numbers?
  2. What are the rules for dealing with negative exponents?
  3. How do you simplify expressions with both multiplication and division?
  4. What is the relationship between exponents and roots?
  5. How can you apply exponent rules to more complex expressions?

Tip: Remember that any number raised to a negative exponent flips the fraction (reciprocal).

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Math Problem Analysis

Mathematical Concepts

Exponents
Multiplication
Division
Negative Exponents
Reciprocals

Formulas

a^n = a * a * ... * a (n times)
(a/b)^{-1} = (b/a)

Theorems

Negative Exponent Rule: a^{-n} = 1/a^n

Suitable Grade Level

Grades 6-8